Chapter 5: Magnetism and Matter

More than two thousand years ago, me shaped and miners in a region of ancient Greece called Magnesia noticed something strange. Certain dark, heavy stones found in the ground could pull small pieces of iron towards them — with no string, no push, no visible contact. These naturally magnetic stones, known today as lodestones, gave us the very word “magnet,” and records of them go back to about 600 BC.

Centuries later, Chinese navigators made an even more remarkable discovery. A sliver of lodestone, floated on water or balanced on a pivot, would slowly swing around and settle pointing in the north–south direction — every single time, anywhere on Earth. By around the eleventh century, this “south-pointing needle” was guiding ships across open seas, long before anyone could explain why it worked. Sailors trusted their lives to a stone whose behaviour was a complete mystery.

Think about what this means: the Earth itself must somehow be acting on the stone. A planet behaving like a magnet, an ordinary rock pulling iron, and a needle that always knows its direction — these puzzles waited centuries for an explanation. In this chapter, we study magnetism as a subject in its own right and finally answer what those ancient sailors could not.

Fig. 5.0

Fig. 5.0 – A floating lodestone compass aligned by Earth’s magnetic field.

NoteCuriosity Corner

Q1. Why does a freely suspended magnet always come to rest pointing in the north–south direction? Q2. If you cut a bar magnet into two pieces hoping to separate its north and south poles, what do you actually get — and why can a single pole never be isolated? Q3. Gauss’s law in electrostatics relates electric flux to enclosed charge. What does the corresponding law for magnetism say, and what deep fact about nature does it express? Q4. A magnet pulls iron strongly, yet seems to have no effect on copper, water or aluminium. Do these materials really feel nothing, or is something weaker happening? Q5. What is special inside iron that lets it become a strong permanent magnet, and why does heating a magnet destroy its magnetism?

By the end of this chapter, you will be able to answer every one of these questions.

5.1 Introduction

Magnetic phenomena are truly universal in nature. Enormous, distant galaxies carry magnetic fields spread across thousands of light years. The tiny, invisible atoms that make up all matter have magnetic effects hidden inside them. Even human beings and animals are permeated through and through by a host of magnetic fields arising from a variety of sources.

The Earth’s own magnetism is far older than we are — it predates human evolution itself. As we saw in the opening story of this chapter, naturally magnetic ore was known in the Greek region of Magnesia as early as 600 BC, and it is from the name of this place that the word magnet comes.

In the previous chapter, we learned something remarkable: moving charges, or electric currents, produce magnetic fields. In other words, electricity and magnetism are not two separate subjects but deeply connected ones. This discovery was made in the early part of the nineteenth century, and the credit for it goes to Oersted, Ampere, Biot and Savart, among others.

In the present chapter, we change our point of view. Instead of treating magnetism as something produced by currents, we take a look at magnetism as a subject in its own right — magnets, magnetic materials, and the laws that govern them.

Let us first collect some commonly known ideas about magnetism. You have probably met most of these in earlier classes, but they now become the starting points of a deeper study.

  1. The Earth behaves as a magnet. Its magnetic field points approximately from the geographic south to the geographic north. This is why the Earth can act on compass needles everywhere on its surface, as shown in Fig. 5.1a.

Fig. 5.1a

Fig. 5.1a – Earth’s magnetic field and its equivalent internal bar magnet.

  1. When a bar magnet is suspended freely — say, hung by a light thread so it can rotate — it always comes to rest pointing in the north–south direction. The tip that points towards the geographic north is called the north pole of the magnet, and the tip that points towards the geographic south is called its south pole.
NoteDefinition

The north pole of a magnet is the end that points towards the geographic north when the magnet is suspended freely; the end that points towards the geographic south is called its south pole.

Q. The north pole of a compass needle is attracted towards the Earth’s geographic north. Since unlike poles attract, what does this tell us about the Earth’s magnetism?

A. The magnetic pole of the Earth located near the geographic north must behave like a magnetic south pole, because it attracts the north poles of magnets. The naming can feel confusing: “north pole of a magnet” is named after the direction it points, not the type of pole sitting near the geographic north.

  1. Like poles repel and unlike poles attract. If the north poles (or the south poles) of two magnets are brought close together, there is a repulsive force between them. Conversely, there is an attractive force between the north pole of one magnet and the south pole of the other.

  2. Magnetic poles always come in pairs — we cannot isolate the north pole or the south pole of a magnet. If a bar magnet is broken into two halves, we do not get a separate north piece and a separate south piece. Instead, we get two similar, complete bar magnets, each with its own north and south pole, though with somewhat weaker properties. This is strikingly different from electric charge: a positive charge can exist entirely on its own, but an isolated magnetic pole — called a magnetic monopole — does not exist.

  3. It is possible to make magnets artificially out of iron and its alloys. This is how the magnets used in everyday devices are manufactured.

These five simple observations raise deep questions: why do poles always come in pairs? Why does the Earth act like a magnet? This chapter builds the physics needed to answer them. We begin with a description of a bar magnet and its behaviour in an external magnetic field. We then describe Gauss’s law of magnetism — the magnetic counterpart of the Gauss’s law you studied in electrostatics. Finally, we describe how materials can be classified on the basis of their magnetic properties, studying three families of materials: diamagnetic, paramagnetic and ferromagnetic substances.

5.2 The Bar Magnet

We begin our study with the simplest and most familiar magnet of all: the bar magnet. A classic way to “see” what a magnet does to the space around it is to sprinkle iron filings on a sheet of glass placed over a short bar magnet. When the glass is tapped gently, the filings arrange themselves into a striking pattern of curved lines, as shown in Fig. 5.2.

Fig. 5.2

Fig. 5.2 – Iron filings tracing the magnetic field of a bar magnet.

Why do the filings do this? Each tiny filing becomes a small magnet in the field of the bar magnet and aligns itself along the local direction of the field. Together, thousands of filings trace out the shape of the magnetic field.

The pattern tells us something important: the filings crowd most densely near the two ends of the magnet. This suggests that the magnet has two poles, playing a role similar to the positive and negative charges of an electric dipole (which you studied in Chapter 1). As mentioned in the introduction, one pole is designated the North pole and the other the South pole, and when the magnet is suspended freely, these poles point approximately towards the geographic north and south, respectively.

Here is a clue worth noting early: a very similar pattern of iron filings is observed around a current-carrying solenoid. A coil of wire carrying current behaves, from the outside, just like a bar magnet. We will make this connection precise in Section 5.2.2.

5.2.1 The magnetic field lines

The pattern of iron filings permits us to plot the magnetic field lines. Field lines are not real physical threads in space — they are a visual and intuitive way of representing the magnetic field, exactly as electric field lines represented the electric field in electrostatics. Figure 5.3 shows the field lines of (a) a bar magnet and (b) a current-carrying finite solenoid; for comparison, the electric field lines of an electric dipole are displayed in Fig. 5.3(c). Notice how, at large distances, all three patterns look very similar.

Fig. 5.3

Fig. 5.3 – Field lines of (a) a bar magnet, (b) a finite solenoid, and (c) an electric dipole.

NoteDefinition

Magnetic field lines are a pictorial representation of the magnetic field. The tangent to a field line at any point gives the direction of the magnetic field \(\vec{B}\) at that point, and the density of lines (number crossing per unit area) represents the strength of the field.

The magnetic field lines have the following properties. Compare each one carefully with what you know about electric field lines — the differences are as important as the similarities.

(i) Magnetic field lines form continuous closed loops. The field lines of a magnet (or a solenoid) never begin or end anywhere; each line closes on itself. This is unlike the electric dipole, where field lines begin on the positive charge and end on the negative charge (or escape to infinity). You can see this clearly in Fig. 5.3: in (a) and (b) the lines loop through the body of the magnet or solenoid and close, while in (c) they start and stop on the charges.

(ii) The tangent gives the direction of the field. The tangent to a field line at a given point represents the direction of the net magnetic field \(\vec{B}\) at that point. If a tiny compass needle is placed there, it aligns along this tangent.

(iii) Line density gives the strength of the field. The larger the number of field lines crossing per unit area, the stronger the magnitude of the magnetic field \(\vec{B}\). In Fig. 5.3(a), the lines are packed more closely around region (ii) than around region (i), so \(\vec{B}\) is larger around region (ii).

(iv) Field lines never intersect. Two magnetic field lines cannot cross each other. If they did, there would be two different tangents — and hence two different directions of \(\vec{B}\) — at the point of intersection. But the magnetic field at a point can have only one direction, so intersection is impossible.

Q. Electric field lines of a dipole also never cross, and their tangent also gives the field direction. Then what is the truly new feature of magnetic field lines?

A. Property (i). Magnetic field lines always form closed loops — they have no starting points and no end points. Electric field lines, by contrast, begin and end on charges. This single difference reflects a deep fact of nature: isolated magnetic poles do not exist, while isolated electric charges do. This idea becomes Gauss’s law of magnetism in Section 5.3.

In some textbooks, magnetic field lines are called “magnetic lines of force.” This name is avoided here because it can be misleading. In electrostatics, the field line direction is also the direction of the force on a positive charge. In magnetism, however, the force on a moving charge is \(q\vec{v} \times \vec{B}\), which is always perpendicular to \(\vec{B}\) — the field line does not point along the force on a (moving) charge.

How does one actually plot magnetic field lines in the laboratory? One can plot them in a variety of ways. One simple way is to place a small magnetic compass needle at various positions around the magnet and note its orientation at each place. The needle’s alignment gives the direction of the magnetic field at that point, and joining up these directions point by point traces out the field lines in space.

5.2.2 Bar magnet as an equivalent solenoid

In the previous chapter (Section 4.9), we explained how a current loop acts as a magnetic dipole: a loop of area \(A\) carrying current \(I\) has a magnetic moment of magnitude \(m = IA\) (and \(m = NIA\) for \(N\) turns), directed along the axis of the loop by the right-hand rule.

We also mentioned Ampere’s hypothesis there — the bold idea that all magnetic phenomena, including those of ordinary magnets, can be explained in terms of circulating currents.

Soon after Oersted’s discovery that currents produce magnetic effects, the French physicist André-Marie Ampère (in the 1820s) proposed that even a permanent magnet owes its magnetism to countless tiny circulating currents inside the material. This was a remarkable leap: at that time, nobody knew about electrons or atoms in the modern sense. Today we know Ampère was essentially right — the orbital motion and spin of electrons inside atoms constitute exactly such microscopic current loops.

NotePrinciple / Law

Ampere’s hypothesis: all magnetic phenomena can be explained in terms of circulating electric currents.

The resemblance between the magnetic field lines of a bar magnet and those of a solenoid, seen in Figs. 5.3(a) and (b), suggests a powerful picture: a bar magnet may be thought of as a large number of circulating currents stacked together, in analogy with the many current-carrying turns of a solenoid.

This picture immediately explains a puzzle from the introduction. Cutting a bar magnet in half is like cutting a solenoid across its middle: we simply get two smaller solenoids, each still a complete solenoid with current circulating around it, and each therefore with its own north and south face — only with weaker magnetic properties. The field lines remain continuous, emerging from one face of each smaller solenoid and entering the other face. No amount of cutting can ever produce an isolated pole, because every piece, however small, still contains complete current loops.

Q2. If you cut a bar magnet into two pieces hoping to separate its north and south poles, what do you actually get — and why can a single pole never be isolated?

A. You get two smaller but complete bar magnets, each with its own north and south pole (only with weaker properties). The reason is clearest from the solenoid picture of a magnet: a bar magnet is equivalent to a solenoid with current circulating around it, and cutting it is like cutting a solenoid across its middle — each half is still a complete solenoid with current loops, and hence still has both faces. Since every piece, however small, still contains complete current loops, an isolated single pole (a magnetic monopole) can never be produced this way.

One can test the bar magnet–solenoid analogy experimentally: move a small compass needle around a bar magnet, and then around a current-carrying finite solenoid, and note that the deflections of the needle are similar in both cases.

To make this analogy more firm, we may calculate the axial field of a finite solenoid — the field at a point P on its axis — as depicted in Fig. 5.4(a). Here the solenoid has length \(2l\), radius \(a\), and P lies at a distance \(r\) from its centre O. We can demonstrate that at large distances (\(r \gg l\) and \(r \gg a\)), this axial field resembles that of a bar magnet.

Fig. 5.4

Fig. 5.4 – (a) Geometry of a finite solenoid and (b) a dipole in a uniform field.

The magnitude of the field at point P due to the solenoid works out to be

\[B = \frac{\mu_0}{4\pi}\,\frac{2m}{r^3} \tag{5.1}\]

Here \(m\) is the total magnetic moment of the solenoid, \(r\) is the distance of P from the centre of the solenoid (in metres, m), \(\mu_0\) is the permeability of free space (\(\mu_0 = 4\pi \times 10^{-7}\) T m A\(^{-1}\)), and \(B\) is in tesla (T). Notice the \(1/r^3\) dependence — the field of a dipole falls off with the cube of the distance, faster than the \(1/r^2\) fall of the field of a single point charge in electrostatics.

The significance of Eq. (5.1) is this: it is also the far axial magnetic field of a bar magnet, which one may obtain experimentally. Thus, a bar magnet and a solenoid produce similar magnetic fields. The magnetic moment of a bar magnet is therefore defined to be equal to the magnetic moment of an equivalent solenoid — one that produces the same magnetic field.

This equivalence is used in reverse in electromagnets. A solenoid wound around a core behaves exactly like a bar magnet whose “strength” can be switched on and off with the current. Scrapyard cranes lift and release heavy iron loads this way, and the same principle operates in electric bells, relays and magnetic locks.

Q. A solenoid’s field can be switched off; a bar magnet’s cannot. Does this break the equivalence between them?

A. No. The equivalence is about the fields they produce while they act as magnets. In a bar magnet, the “current” is due to electrons inside atoms and cannot be switched off from outside; in a solenoid, we control the current externally. The external field patterns, and the expression (5.1), are the same in both cases.

5.2.3 The dipole in a uniform magnetic field

Having established what a bar magnet is, we now ask how it behaves when placed in an external magnetic field. Let us place a small compass needle of known magnetic moment \(\vec{m}\) in a uniform magnetic field \(\vec{B}\) and allow it to oscillate. This arrangement is shown in Fig. 5.4(b).

The torque on the needle is [see Eq. (4.23) of the previous chapter],

\[\vec{\tau} = \vec{m} \times \vec{B} \tag{5.2}\]

In magnitude,

\[\tau = mB\sin\theta\]

Here \(\tau\) is the restoring torque (SI unit: N m), \(m\) is the magnitude of the magnetic moment (A m\(^2\), equivalently J T\(^{-1}\)), \(B\) is the magnetic field (T), and \(\theta\) is the angle between \(\vec{m}\) and \(\vec{B}\).

Why “restoring”? Whenever the needle is turned away from the field direction, this torque acts to rotate it back towards alignment with \(\vec{B}\) — just as gravity pulls a displaced pendulum back towards the vertical. If disturbed, the needle therefore oscillates about the field direction.

This is precisely why a freely suspended magnet, or a compass needle, always settles pointing north–south. The Earth’s magnetic field exerts a torque \(\vec{m} \times \vec{B}\) on the needle whenever its moment is not aligned with the field; the needle swings, loses energy to friction, and finally comes to rest with \(\vec{m}\) along the Earth’s field — which runs approximately south to north.

Q1. Why does a freely suspended magnet always come to rest pointing in the north–south direction?

A. Because the Earth itself behaves as a magnet, and a suspended magnet is a magnetic dipole. Whenever the magnet’s moment \(\vec{m}\) is not aligned with the Earth’s field \(\vec{B}\), the field exerts a torque \(\vec{m}\times\vec{B}\) on it. The magnet swings under this torque, gradually loses energy to friction, and finally settles with \(\vec{m}\) along the Earth’s field — which runs approximately south to north — so it comes to rest pointing north–south.

Since the field exerts a torque on the dipole, work must be done by an external agent to rotate the dipole against this torque. That work gets stored as magnetic potential energy, in exactly the same way that work done against the electric torque on an electric dipole was stored as electrostatic potential energy (Chapter 1).

The magnetic potential energy \(U_m\) is obtained by integrating the torque over the angle turned:

\[U_m = \int \tau(\theta)\, d\theta\]

\[= \int mB \sin\theta \, d\theta = -mB\cos\theta\]

\[= -\vec{m}\cdot\vec{B} \tag{5.3}\]

The middle step uses the standard integral \(\int \sin\theta \, d\theta = -\cos\theta\), and the last step recognises that \(mB\cos\theta\) is exactly the dot product \(\vec{m}\cdot\vec{B}\).

You may ask: an indefinite integral should carry a constant of integration — where has it gone? We have emphasised in Chapter 2 that the zero of potential energy can be fixed at one’s convenience. Taking the constant of integration to be zero amounts to fixing the zero of potential energy at \(\theta = 90°\), i.e., when the needle is perpendicular to the field.

With this convention, Eq. (5.3) tells us the whole energy story of the dipole:

  • Potential energy is minimum, \(U_m = -mB\), at \(\theta = 0°\) (moment parallel to field). This is the most stable position.
  • Potential energy is maximum, \(U_m = +mB\), at \(\theta = 180°\) (moment antiparallel to field). This is the most unstable position.

Q. Both θ = 0° and θ = 180° are positions where the torque mB sin θ vanishes. Why is one stable and the other unstable?

A. Look at what happens on a slight disturbance. At θ = 0°, a small tilt produces a torque that pushes the dipole back to alignment — energy would have to increase for it to move away, so it returns: stable. At θ = 180°, a small tilt produces a torque that pushes the dipole further away, towards θ = 0°: unstable. Stability always corresponds to a minimum of potential energy.

In examinations, this idea is typically tested through numericals asking for the torque at a given angle, the work done in rotating a magnet from one orientation to another (\(W = U_{final} - U_{initial}\)), or identification of stable/unstable equilibrium positions. Keep the sign convention of Eq. (5.3) firmly in mind — most errors come from dropped minus signs.

A bar magnet of magnetic moment \(0.40\) J T\(^{-1}\) is placed in a uniform magnetic field of \(0.25\) T with its moment making an angle of \(30°\) with the field. Calculate (a) the magnitude of the torque on the magnet, (b) its potential energy in this orientation, and (c) the work required to rotate it from this position to the position of unstable equilibrium.

(a) What happens if a bar magnet is cut into two pieces: (i) transverse to its length, (ii) along its length?

(b) A magnetised needle in a uniform magnetic field experiences a torque but no net force. An iron nail near a bar magnet, however, experiences a force of attraction in addition to a torque. Why?

(c) Must every magnetic configuration have a north pole and a south pole? What about the field due to a toroid?

(d) Two identical looking iron bars A and B are given, one of which is definitely known to be magnetised. (We do not know which one.) How would one ascertain whether or not both are magnetised? If only one is magnetised, how does one ascertain which one? [Use nothing else but the bars A and B.]

Solution

  1. In either case, one gets two magnets, each with a north and south pole. (This follows directly from the solenoid picture of Section 5.2.2 — every piece still contains complete current loops.)

  2. No force if the field is uniform. The iron nail experiences a non-uniform field due to the bar magnet. There is induced magnetic moment in the nail; therefore, it experiences both force and torque. The net force is attractive because the induced south pole (say) in the nail is closer to the north pole of the magnet than the induced north pole.

  3. Not necessarily. This is true only if the source of the field has a net non-zero magnetic moment. This is not so for a toroid, or even for a straight infinite conductor.

  4. Try to bring different ends of the bars closer. A repulsive force in some situation establishes that both are magnetised. If it is always attractive, then one of them is not magnetised. In a bar magnet the intensity of the magnetic field is the strongest at the two ends (poles) and weakest at the central region. This fact may be used to determine whether A or B is the magnet. In this case, to see which one of the two bars is a magnet, pick up one, (say, A) and lower one of its ends; first on one of the ends of the other (say, B), and then on the middle of B. If you notice that in the middle of B, A experiences no force, then B is magnetised. If you do not notice any change from the end to the middle of B, then A is magnetised.

5.2.4 The electrostatic analog

If you place Eqs. (5.1), (5.2) and (5.3) side by side with the corresponding equations for the electric dipole from Chapter 1, a beautiful pattern emerges: the two sets of equations are identical in form. The magnetic field at large distances due to a bar magnet of magnetic moment \(\vec{m}\) can be obtained from the equations for the electric field of an electric dipole of dipole moment \(\vec{p}\), simply by making the following replacements:

\[\vec{E} \rightarrow \vec{B}, \quad \vec{p} \rightarrow \vec{m}, \quad \frac{1}{4\pi\varepsilon_0} \rightarrow \frac{\mu_0}{4\pi}\]

This is a translation dictionary between electrostatics and magnetism. Any far-field result you derived for the electric dipole can be instantly rewritten for the magnetic dipole — no fresh derivation needed.

In particular, we can write down the equatorial field (\(\vec{B}_E\)) of a bar magnet — the field at a point on the perpendicular bisector of the magnet — at a distance \(r\), for \(r \gg l\), where \(l\) is the size of the magnet:

\[\vec{B}_E = -\frac{\mu_0 \vec{m}}{4\pi r^3} \tag{5.4}\]

The minus sign says that on the equatorial line, the field points opposite to the magnetic moment \(\vec{m}\), exactly as the equatorial electric field of an electric dipole points opposite to \(\vec{p}\).

Likewise, the axial field (\(\vec{B}_A\)) of a bar magnet for \(r \gg l\) is:

\[\vec{B}_A = \frac{\mu_0}{4\pi}\,\frac{2\vec{m}}{r^3} \tag{5.5}\]

Equation (5.5) is just Eq. (5.1) in vector form. On the axis, the field is parallel to \(\vec{m}\) and is twice as strong as the equatorial field at the same distance. The condition \(r \gg l\) (“short dipole” or “far field”) is essential — these compact formulas hold only far from the magnet compared with its own size, and dropping this condition is a common examination error.

Table 5.1 summarises the analogy between electric and magnetic dipoles. As shown in the table, every electrostatic dipole quantity has a magnetic twin.

Table 5.1 – The Dipole Analogy

Electrostatics Magnetism
\(1/\varepsilon_0\) \(\mu_0\)
Dipole moment \(\vec{p}\) \(\vec{m}\)
Equatorial field for a short dipole \(-\vec{p}/4\pi\varepsilon_0 r^3\) \(-\mu_0\vec{m}/4\pi r^3\)
Axial field for a short dipole \(2\vec{p}/4\pi\varepsilon_0 r^3\) \(\mu_0 2\vec{m}/4\pi r^3\)
External field: torque \(\vec{p} \times \vec{E}\) \(\vec{m} \times \vec{B}\)
External field: energy \(-\vec{p}\cdot\vec{E}\) \(-\vec{m}\cdot\vec{B}\)

In numerical problems, Eqs. (5.4) and (5.5) are most often tested by asking for the field at a given distance on the axis or the equator, or by comparing the two (“at what point is the field the same…?”). Remember the factor of 2 and the direction reversal on the equatorial line.

A short bar magnet has a magnetic moment of \(0.90\) J T\(^{-1}\). Find the magnitude and direction of the magnetic field due to the magnet at a distance of \(15\) cm from its centre (a) on the axis of the magnet, and (b) on its equatorial line.

Figure 5.5 shows a small magnetised needle P placed at a point O. The arrow shows the direction of its magnetic moment. The other arrows show different positions (and orientations of the magnetic moment) of another identical magnetised needle Q.

(a) In which configuration is the system not in equilibrium?

(b) In which configuration is the system in (i) stable, and (ii) unstable equilibrium?

(c) Which configuration corresponds to the lowest potential energy among all the configurations shown?

Fig. 5.5

[Caption:] Fig. 5.5 – A magnetic needle P and an identical needle Q at various positions. [/Caption:]

Solution

The potential energy of the configuration arises due to the potential energy of one dipole (say, Q) in the magnetic field due to the other (P). Use the result that the field due to P is given by the expressions [Eqs. (5.4) and (5.5)]:

\[\vec{B}_P = -\frac{\mu_0}{4\pi}\,\frac{\vec{m}_P}{r^3} \quad \text{(on the normal bisector)}\]

\[\vec{B}_P = \frac{\mu_0}{4\pi}\,\frac{2\,\vec{m}_P}{r^3} \quad \text{(on the axis)}\]

where \(\vec{m}_P\) is the magnetic moment of the dipole P.

Equilibrium is stable when \(\vec{m}_Q\) is parallel to \(\vec{B}_P\), and unstable when it is anti-parallel to \(\vec{B}_P\). For instance, for the configuration Q\(_3\), for which Q is along the perpendicular bisector of the dipole P, the magnetic moment of Q is parallel to the magnetic field at position 3. Hence Q\(_3\) is stable.

Thus,

  1. PQ\(_1\) and PQ\(_2\)

    1. PQ\(_3\), PQ\(_6\) (stable); (ii) PQ\(_5\), PQ\(_4\) (unstable)
  2. PQ\(_6\)

5.3 Magnetism and Gauss’s Law

In Chapter 1, we studied Gauss’s law for electrostatics: the electric flux through a closed surface is proportional to the total charge enclosed by it. We now ask the natural question — is there a corresponding law for magnetism? The answer turns out to be yes, and it is short, elegant, and packed with physical meaning.

Look again at the electric dipole in Fig. 5.3(c). For the closed surface labelled (i), the number of field lines leaving the surface is equal to the number of lines entering it. This is consistent with the fact that no net charge is enclosed by that surface. However, in the same figure, for the closed surface (ii), there is a net outward flux, because this surface does enclose a net (positive) charge.

The situation is radically different for magnetic fields, which are continuous and form closed loops. Examine the Gaussian surfaces labelled (i) or (ii) in Fig. 5.3(a) or Fig. 5.3(b). Both cases visually demonstrate the same thing: every field line that leaves the surface also comes back and enters it, because each line is a closed loop. The number of magnetic field lines leaving the surface is balanced by the number of lines entering it. The net magnetic flux is zero for both the surfaces — and this is true for any closed surface whatsoever, however oddly shaped, wherever placed.

Let us express this precisely. Consider a small vector area element \(\Delta\vec{S}\) of a closed surface S, as in Fig. 5.6. Recall from Chapter 1 that an area element is treated as a vector whose direction is along the outward normal \(\hat{n}\) to the surface.

Fig. 5.6

Fig. 5.6 – Magnetic flux through a small area element.

The magnetic flux through \(\Delta\vec{S}\) is defined as

\[\Delta\phi_B = \vec{B}\cdot\Delta\vec{S}\]

where \(\vec{B}\) is the field at \(\Delta\vec{S}\). Flux, loosely speaking, counts how much of the field “flows through” the little area; the dot product automatically takes care of the angle between the field and the surface. The SI unit of magnetic flux is the weber (Wb), where \(1\ \text{Wb} = 1\ \text{T m}^2\).

NoteDefinition

The magnetic flux through a small area element is \(\Delta\phi_B = \vec{B}\cdot\Delta\vec{S}\), where \(\vec{B}\) is the magnetic field at the element and \(\Delta\vec{S}\) is the area vector along the outward normal. Its SI unit is the weber (Wb).

Now we divide the entire closed surface S into many small area elements and calculate the individual flux through each. The net flux \(\phi_B\) is the sum over all of them:

\[\phi_B = \sum_{\text{'all'}} \Delta\phi_B = \sum_{\text{'all'}} \vec{B}\cdot\Delta\vec{S} = 0 \tag{5.6}\]

where ‘all’ stands for ‘all area elements \(\Delta\vec{S}\)’ of the closed surface.

Compare this with Gauss’s law of electrostatics. The flux through a closed surface in that case is given by

\[\sum \vec{E}\cdot\Delta\vec{S} = \frac{q}{\varepsilon_0}\]

where \(q\) is the electric charge enclosed by the surface.

The contrast is striking. In electrostatics, the right-hand side can be non-zero, because electric charges — the sources and sinks on which field lines begin and end — can be enclosed by a surface. In magnetism, the right-hand side is always zero. The difference between Gauss’s law of magnetism and that of electrostatics is a reflection of the fact that isolated magnetic poles (also called monopoles) are not known to exist. There are no sources or sinks of \(\vec{B}\). The simplest magnetic element is a dipole or a current loop, and all magnetic phenomena can be explained in terms of an arrangement of dipoles and/or current loops.

Thus, Gauss’s law for magnetism is:

NotePrinciple / Law

The net magnetic flux through any closed surface is zero: \[\phi_B = \sum_{\text{all}} \vec{B}\cdot\Delta\vec{S} = 0\]

This law is the mathematical statement of the fact you have now met three times in this chapter — as the impossibility of isolating a pole by cutting a magnet, as the closed-loop property of field lines, and now as a flux law for any closed surface. All three are one and the same physical truth.

Q3. Gauss’s law in electrostatics relates electric flux to enclosed charge. What does the corresponding law for magnetism say, and what deep fact about nature does it express?

A. Gauss’s law for magnetism states that the net magnetic flux through any closed surface is always zero. Unlike electric field lines, which begin and end on charges, magnetic field lines form continuous closed loops, so as many lines leave a closed surface as enter it. The deep fact this expresses is that isolated magnetic poles (monopoles) do not exist: there is no magnetic ‘charge’ to act as a source or sink of flux, which is the same truth seen when cutting a magnet never yields a single pole.

Q. The net magnetic flux through a closed surface is always zero. Does this mean the magnetic field itself is zero on the surface?

A. No. The field can be strong everywhere on the surface. Zero net flux only means that whatever flux enters the surface through some parts exits through others — inflow and outflow always balance exactly. A closed surface drawn around one pole of a strong bar magnet has large fields all over it, yet its net flux is still zero.

In exams, this law appears in two common ways: conceptual questions (“why is the net magnetic flux through a closed surface zero?”) and numericals where the flux through part of a closed surface is given and you must find the flux through the rest, using the fact that all contributions must add to zero.

A closed surface is in the shape of a cylinder placed in a magnetic field. The magnetic flux entering the cylinder through one flat face is \(25\) mWb, and the flux leaving through the other flat face is \(18\) mWb. Find the magnitude and sense (inward or outward) of the net magnetic flux through the curved surface of the cylinder.

Karl Friedrich Gauss (1777–1855), after whom this law is named, was a child prodigy gifted in mathematics, physics, engineering, astronomy and even land surveying. The properties of numbers fascinated him, and in his work he anticipated major mathematical developments of later times. Along with Wilhelm Welser, he built the first electric telegraph in 1833. His mathematical theory of curved surfaces laid the foundation for the later work of Riemann.

Physicists have not stopped looking for magnetic monopoles. In 1931, the theoretical physicist P. A. M. Dirac showed that if even a single magnetic monopole existed anywhere in the universe, it would explain why electric charge comes in fixed multiples of the electronic charge. This tantalising prediction has driven decades of experimental searches — in particle accelerators, cosmic rays, and rock samples — but no confirmed monopole has ever been found. Gauss’s law for magnetism, with its firm zero on the right-hand side, still stands.

Many of the diagrams given in Fig. 5.7 show magnetic field lines (thick lines in the figure) wrongly. Point out what is wrong with them. Some of them may describe electrostatic field lines correctly. Point out which ones.

Fig. 5.7

[Caption:] Fig. 5.7 – Various correct and incorrect sketches of field lines. [/Caption:]

Solution

  1. Wrong. Magnetic field lines can never emanate from a point, as shown in the figure. Over any closed surface, the net flux of \(\vec{B}\) must always be zero, i.e., pictorially, as many field lines should seem to enter the surface as the number of lines leaving it. The field lines shown, in fact, represent the electric field of a long positively charged wire. The correct magnetic field lines circle around the straight conductor, as described in Chapter 4.

  2. Wrong. Magnetic field lines (like electric field lines) can never cross each other, because otherwise the direction of the field at the point of intersection would be ambiguous. There is a further error in the figure: magnetostatic field lines can never form closed loops around empty space. A closed loop of a static magnetic field line must enclose a region across which a current is passing. By contrast, electrostatic field lines can never form closed loops, neither in empty space, nor when the loop encloses charges.

  3. Right. Magnetic lines are completely confined within a toroid. Nothing is wrong here in field lines forming closed loops, since each loop encloses a region across which a current passes. Note, for clarity of the figure, only a few field lines within the toroid have been shown. Actually, the entire region enclosed by the windings contains magnetic field.

  4. Wrong. Field lines due to a solenoid at its ends and outside cannot be so completely straight and confined; such a thing violates Ampere’s law. The lines should curve out at both ends, and meet eventually to form closed loops.

  5. Right. These are field lines outside and inside a bar magnet. Note carefully the direction of field lines inside. Not all field lines emanate out of a north pole (or converge into a south pole). Around both the N-pole and the S-pole, the net flux of the field is zero.

  6. Wrong. These field lines cannot possibly represent a magnetic field. Look at the upper region. All the field lines seem to emanate out of the shaded plate. The net flux through a surface surrounding the shaded plate is not zero. This is impossible for a magnetic field. The given field lines, in fact, show the electrostatic field lines around a positively charged upper plate and a negatively charged lower plate. The difference between Figs. [5.7(e) and (f)] should be carefully grasped.

  7. Wrong. Magnetic field lines between two pole pieces cannot be precisely straight at the ends. Some fringing of lines is inevitable. Otherwise, Ampere’s law is violated. This is also true for electric field lines.

(a) Magnetic field lines show the direction (at every point) along which a small magnetised needle aligns (at the point). Do the magnetic field lines also represent the lines of force on a moving charged particle at every point?

(b) If magnetic monopoles existed, how would the Gauss’s law of magnetism be modified?

(c) Does a bar magnet exert a torque on itself due to its own field? Does one element of a current-carrying wire exert a force on another element of the same wire?

(d) Magnetic field arises due to charges in motion. Can a system have magnetic moments even though its net charge is zero?

Solution

  1. No. The magnetic force is always normal to \(\vec{B}\) (remember, magnetic force \(= q\vec{v} \times \vec{B}\)). It is misleading to call magnetic field lines lines of force.

  2. Gauss’s law of magnetism states that the flux of \(\vec{B}\) through any closed surface is always zero: \(\int_S \vec{B}\cdot\Delta\vec{s} = 0\).

If monopoles existed, the right-hand side would be equal to the monopole (magnetic charge) \(q_m\) enclosed by S. [Analogous to Gauss’s law of electrostatics, \(\int_S \vec{B}\cdot\Delta\vec{s} = \mu_0 q_m\), where \(q_m\) is the (monopole) magnetic charge enclosed by S.]

  1. No. There is no force or torque on an element due to the field produced by that element itself. But there is a force (or torque) on an element of the same wire due to the field produced by another element of the same wire. (For the special case of a straight wire, this force is zero.)

  2. Yes. The average of the charge in the system may be zero. Yet, the mean of the magnetic moments due to various current loops may not be zero. We will come across such examples in connection with paramagnetic material, where atoms have a net dipole moment even though their net charge is zero.

5.4 Magnetisation and Magnetic Intensity

The Earth abounds with a bewildering variety of elements and compounds. In addition, we have been synthesising new alloys, compounds and even elements. Faced with this variety, a physicist naturally asks: can we classify all these substances by their magnetic behaviour? To carry out this exercise, we first need a small vocabulary of precisely defined quantities. In the present section, we define and explain these terms; in the next section, we use them to sort all materials into three great families.

Magnetisation

We have seen that a circulating electron in an atom has a magnetic moment — it is a tiny current loop. In a bulk material, which contains an enormous number of atoms, these tiny moments add up vectorially. Depending on how they are oriented, the vector sum can cancel out to zero, or it can give a net magnetic moment which is non-zero.

To describe this on a per-volume basis, we define the magnetisation \(\vec{M}\) of a sample to be equal to its net magnetic moment per unit volume:

\[\vec{M} = \frac{\vec{m}_{net}}{V} \tag{5.7}\]

Here \(\vec{m}_{net}\) is the vector sum of all the atomic magnetic moments in the sample (unit: A m\(^2\)) and \(V\) is its volume (m\(^3\)). \(\vec{M}\) is a vector with dimensions [L\(^{-1}\) A] and is measured in units of A m\(^{-1}\).

NoteDefinition

The magnetisation \(\vec{M}\) of a sample is its net magnetic moment per unit volume: \(\vec{M} = \vec{m}_{net}/V\). It is a vector, measured in A m\(^{-1}\).

Magnetisation answers the question “how strongly magnetised is this material, per unit volume?” — just as density answers “how much mass, per unit volume?”

The field inside a magnetised material

Now let us see how magnetisation modifies a magnetic field. Consider a long solenoid with \(n\) turns per unit length, carrying a current \(I\). In the previous chapter, the magnetic field in the interior of such a solenoid (with vacuum or air inside) was shown to be

\[B_0 = \mu_0 n I \tag{5.8}\]

where \(\mu_0\) is the permeability of vacuum, \(n\) is in turns per metre and \(I\) in amperes.

If the interior of the solenoid is now filled with a material having non-zero magnetisation, something interesting happens: the field inside becomes greater than \(B_0\). The material’s own atomic moments, aligned by the solenoid’s field, contribute an additional field of their own. The net \(\vec{B}\) field in the interior of the solenoid may then be expressed as

\[\vec{B} = \vec{B}_0 + \vec{B}_m \tag{5.9}\]

where \(\vec{B}_m\) is the field contributed by the material core. It turns out that this additional field \(\vec{B}_m\) is proportional to the magnetisation \(\vec{M}\) of the material, and is expressed as

\[\vec{B}_m = \mu_0 \vec{M} \tag{5.10}\]

where \(\mu_0\) is the same constant (permeability of vacuum) that appears in the Biot–Savart law.

Magnetic intensity H

Look carefully at what we have: the total field inside the material has two distinct causes. One part comes from the current we send through the solenoid — something we control externally. The other part comes from the response of the material itself. It is extremely convenient to give the externally controlled part its own name and symbol.

We introduce another vector field \(\vec{H}\), called the magnetic intensity, defined by

\[\vec{H} = \frac{\vec{B}}{\mu_0} - \vec{M} \tag{5.11}\]

where \(\vec{H}\) has the same dimensions as \(\vec{M}\) and is measured in units of A m\(^{-1}\).

NoteDefinition

The magnetic intensity is the vector field \(\vec{H} = \dfrac{\vec{B}}{\mu_0} - \vec{M}\). It represents the contribution of external factors (such as the current in the solenoid) to the magnetic field inside a material, and is measured in A m\(^{-1}\).

Rearranging Eq. (5.11), the total magnetic field \(\vec{B}\) is written as

\[\vec{B} = \mu_0(\vec{H} + \vec{M}) \tag{5.12}\]

Let us repeat our defining procedure in words, because this partition is the key idea of the section. We have divided the contribution to the total magnetic field inside the sample into two parts: one, due to external factors such as the current in the solenoid — this is represented by \(\vec{H}\); the other, due to the specific nature of the magnetic material — namely \(\vec{M}\).

This is closely parallel to what you did with dielectrics in electrostatics (Chapter 2): there, the applied field polarised the dielectric, and the material’s polarisation modified the net field inside. Here, the applied field magnetises the material, and the magnetisation modifies the net field inside.

Q. We now have two field-like quantities, \(\vec{B}\) and \(\vec{H}\). What is the physical difference between them?

A. \(\vec{H}\) keeps track of only the external cause — in a solenoid, \(H = nI\) depends only on the winding and the current, not on what fills the core. \(\vec{B}\) is the total, actual magnetic field inside, which includes the material’s response \(\mu_0\vec{M}\) as well. Change the core material and \(\vec{B}\) changes, but \(\vec{H}\) does not. This is why \(H\) is defined “for convenience”: it separates what we control from what the material does.

Susceptibility and permeability

The material’s response \(\vec{M}\) is not independent of the external influence — it can be influenced by external factors. For a large class of materials, this influence is mathematically simple: the magnetisation is directly proportional to the magnetic intensity,

\[\vec{M} = \chi \vec{H} \tag{5.13}\]

where \(\chi\) (the Greek letter chi), a dimensionless quantity, is appropriately called the magnetic susceptibility. It is a measure of how a magnetic material responds to an external field — literally, how “susceptible” the material is to becoming magnetised.

NoteDefinition

The magnetic susceptibility \(\chi\) is the dimensionless ratio of the magnetisation to the magnetic intensity, \(\vec{M} = \chi\vec{H}\), for a linear material. It measures how readily a material becomes magnetised in an external field.

The sign of \(\chi\) immediately sorts materials into classes. \(\chi\) is small and positive for materials which are called paramagnetic — their magnetisation supports the external field. \(\chi\) is small and negative for materials which are termed diamagnetic — in this latter case, \(\vec{M}\) and \(\vec{H}\) are opposite in direction, so the material weakly opposes the field. We will study both classes, and a third dramatic one, in Section 5.5.

From Eqs. (5.12) and (5.13) we obtain, by substituting \(\vec{M} = \chi\vec{H}\):

\[\vec{B} = \mu_0(1 + \chi)\vec{H} \tag{5.14}\]

\[= \mu_0\,\mu_r\,\vec{H}\]

\[= \mu\,\vec{H} \tag{5.15}\]

where \(\mu_r = 1 + \chi\) is a dimensionless quantity called the relative magnetic permeability of the substance. It is the analog of the dielectric constant in electrostatics — it tells us by what factor the material multiplies the field compared to vacuum.

The magnetic permeability of the substance is \(\mu\), and it has the same dimensions and units as \(\mu_0\):

\[\mu = \mu_0\mu_r = \mu_0(1 + \chi)\]

NoteDefinition

The relative magnetic permeability of a substance is \(\mu_r = 1 + \chi\) (dimensionless), and its magnetic permeability is \(\mu = \mu_0\mu_r = \mu_0(1+\chi)\), with the same units as \(\mu_0\) (T m A\(^{-1}\)).

Note that the three quantities \(\chi\), \(\mu_r\) and \(\mu\) are interrelated, and only one of them is independent. Given any one, the other two may be easily determined. In numerical problems, you will often be given one of these and asked for the others — the chains \(\mu_r = 1 + \chi\) and \(\mu = \mu_0\mu_r\) are all you need.

This is why practical coils are rarely air-filled. The inductors on a mobile-phone charger board and the cores of power transformers are wound on ferrite or iron-based materials with large \(\mu_r\): the same current then produces a vastly larger \(B\) inside, making the device compact and efficient. Choosing a core material is essentially choosing a value of \(\mu_r\).

A long solenoid with 750 turns per metre carries a current of \(1.2\) A. Its core is filled with a paramagnetic material of magnetic susceptibility \(\chi = 4.0 \times 10^{-4}\). Calculate (a) the magnetic intensity \(H\) inside the solenoid, (b) the magnetisation \(M\) of the core, and (c) the total magnetic field \(B\) inside the core.

A solenoid has a core of a material with relative permeability 400. The windings of the solenoid are insulated from the core and carry a current of 2 A. If the number of turns is 1000 per metre, calculate (a) \(H\), (b) \(M\), (c) \(B\) and (d) the magnetising current \(I_m\).

Solution

  1. The field \(H\) depends only on external factors — the winding and the current — and not on the material of the core:

\[H = nI = 1000 \times 2.0 = 2 \times 10^3 \ \text{A/m}\]

  1. The magnetic field \(B\) is given by (using Eq. 5.15, since \(\mu_r\) is known):

\[B = \mu_r \mu_0 H = 400 \times 4\pi \times 10^{-7}\ (\text{N/A}^2) \times 2 \times 10^3\ (\text{A/m}) = 1.0 \ \text{T}\]

  1. Magnetisation is given by (rearranging Eq. 5.12):

\[M = (B - \mu_0 H)/\mu_0 = (\mu_r\mu_0 H - \mu_0 H)/\mu_0 = (\mu_r - 1)H = 399 \times H \cong 8 \times 10^5 \ \text{A/m}\]

  1. The magnetising current \(I_M\) is the additional current that needs to be passed through the windings of the solenoid in the absence of the core which would give a \(B\) value as in the presence of the core. Thus \(B = \mu_r n (I + I_M)\). Using \(I = 2\) A, \(B = 1\) T, we get \(I_M = 794\) A.

5.5 Magnetic Properties of Materials

The vocabulary developed in the previous section now pays off. Using the susceptibility \(\chi\), we can classify every material into one of three great families of magnetic behaviour.

A material is diamagnetic if \(\chi\) is negative, paramagnetic if \(\chi\) is positive and small, and ferromagnetic if \(\chi\) is large and positive. A glance at Table 5.2 gives one a better feeling for these materials. Here \(\varepsilon\) is a small positive number introduced to quantify paramagnetic materials.

Table 5.2

Diamagnetic Paramagnetic Ferromagnetic
\(-1 \le \chi < 0\) \(0 < \chi < \varepsilon\) \(\chi \gg 1\)
\(0 \le \mu_r < 1\) \(1 < \mu_r < 1 + \varepsilon\) \(\mu_r \gg 1\)
\(\mu < \mu_0\) \(\mu > \mu_0\) \(\mu \gg \mu_0\)

Read the table as a story: diamagnetic materials weakly oppose an applied field (\(\mu\) slightly less than \(\mu_0\)), paramagnetic materials weakly support it (\(\mu\) slightly more than \(\mu_0\)), and ferromagnetic materials support it enormously (\(\mu \gg \mu_0\)). Next, we describe these three families in some detail.

5.5.1 Diamagnetism

Diamagnetic substances are those which have a tendency to move from the stronger to the weaker part of an external magnetic field. In other words, unlike the way a magnet attracts metals like iron, it would repel a diamagnetic substance.

Figure 5.8(a) shows a bar of diamagnetic material placed in an external magnetic field. The field lines are repelled or expelled, and the field inside the material is reduced. In most cases, this reduction is slight, being about one part in \(10^5\). When placed in a non-uniform magnetic field, the bar will tend to move from the region of high field to the region of low field.

Fig. 5.8

Fig. 5.8 – Magnetic field lines near (a) diamagnetic and (b) paramagnetic bars.

Why should any material oppose a magnetic field? The simplest explanation for diamagnetism is as follows. Electrons in an atom, orbiting around the nucleus, possess orbital angular momentum. These orbiting electrons are equivalent to current-carrying loops, and thus possess orbital magnetic moment. Diamagnetic substances are the ones in which the resultant magnetic moment of an atom is zero — the moments of the various electrons cancel out.

When a magnetic field is applied, this balance is disturbed. Those electrons having orbital magnetic moment in the same direction as the field slow down, and those in the opposite direction speed up. This happens due to induced currents, in accordance with Lenz’s law, which you will study in Chapter 6 — the induced effect always opposes the change that causes it. Thus, the substance develops a small net magnetic moment in the direction opposite to that of the applied field, and hence there is repulsion.

Some diamagnetic materials are bismuth, copper, lead, silicon, nitrogen (at STP), water and sodium chloride.

An important subtlety: diamagnetism is present in all substances, because every substance has orbiting electrons. However, the effect is so weak that in most materials it gets overshadowed by other, stronger effects like paramagnetism and ferromagnetism. We only “see” diamagnetism in materials that have nothing stronger to hide it.

Q. Water is diamagnetic. Why do we never notice a magnet repelling water in daily life?

A. The effect is tiny — the field change inside is about one part in 100000, so the repulsive force from an ordinary magnet is far too small to notice against gravity and other forces. Only with extremely strong fields in laboratories does the diamagnetic repulsion of water-rich objects become visible.

The most exotic diamagnetic materials are superconductors. These are metals cooled to very low temperatures, which exhibit both perfect conductivity and perfect diamagnetism. Here the field lines are completely expelled from the material — not merely reduced by one part in \(10^5\), but pushed out entirely. For a superconductor, \(\chi = -1\) and \(\mu_r = 0\): it is the extreme end of the diamagnetic range in Table 5.2.

A superconductor therefore repels a magnet and — by Newton’s third law — is repelled by the magnet. The phenomenon of perfect diamagnetism in superconductors is called the Meissner effect, after the name of its discoverer.

The German physicist Walther Meissner, working with Robert Ochsenfeld in the 1930s, discovered that a superconductor does not merely resist a magnetic field — it actively expels magnetic flux from its interior when cooled into the superconducting state. This was unexpected: perfect conductivity alone could not explain it. The complete quantum-mechanical explanation of superconductivity came only decades later.

Superconducting magnets can be gainfully exploited in a variety of situations — most famously, for running magnetically levitated (maglev) superfast trains. A magnet floating above a superconductor stays suspended because the expelled field lines produce a stable repulsive “cushion”; trains built on this principle glide without touching the track, eliminating rolling friction entirely.

5.5.2 Paramagnetism

Paramagnetic substances are those which get weakly magnetised when placed in an external magnetic field. They have a tendency to move from a region of weak magnetic field to a region of strong magnetic field — i.e., they get weakly attracted to a magnet. Their behaviour is opposite in sense to diamagnetism, but comparable in weakness.

The microscopic picture is quite different from the diamagnetic case. The individual atoms (or ions or molecules) of a paramagnetic material possess a permanent magnetic dipole moment of their own — the electronic moments inside each atom do not fully cancel. So why isn’t every paramagnetic material a magnet already? On account of the ceaseless random thermal motion of the atoms, the moments point in all directions and no net magnetisation is seen.

In the presence of an external field \(\vec{B}_0\) which is strong enough, and at low temperatures, the individual atomic dipole moments can be made to align and point in the same direction as \(\vec{B}_0\). Alignment is a tug-of-war: the field tries to line the dipoles up, while thermal agitation tries to randomise them. A stronger field or a lower temperature tips the contest in favour of alignment.

Figure 5.8(b) shows a bar of paramagnetic material placed in an external field. The field lines get concentrated inside the material, and the field inside is enhanced. In most cases, this enhancement is slight, being about one part in \(10^5\). When placed in a non-uniform magnetic field, the bar will tend to move from the weak-field region to the strong-field region — notice in Fig. 5.8 how this is exactly opposite to the diamagnetic bar of part (a).

Some paramagnetic materials are aluminium, sodium, calcium, oxygen (at STP) and copper chloride.

So we can now answer a question raised at the start of this chapter. Copper, water and aluminium are not indifferent to a magnet. Copper and water are diamagnetic — feebly repelled; aluminium is paramagnetic — feebly attracted. Every material responds to a magnetic field; it is only that these responses are about a hundred thousand times weaker than that of iron, and so escape our notice in everyday life.

Q4. A magnet pulls iron strongly, yet seems to have no effect on copper, water or aluminium. Do these materials really feel nothing, or is something weaker happening?

A. They do respond — just very weakly. Copper and water are diamagnetic and are feebly repelled by a magnet, while aluminium is paramagnetic and is feebly attracted. Every material reacts to a magnetic field; it is only that these responses are roughly a hundred thousand times weaker than that of iron, so they normally escape notice in everyday life.

For a paramagnetic material, both \(\chi\) and \(\mu_r\) depend not only on the material but also (in a simple fashion) on the sample temperature. As the field is increased or the temperature is lowered, the magnetisation increases, until it reaches the saturation value, at which point all the dipoles are perfectly aligned with the field. Beyond saturation, no further increase of magnetisation is possible — there is nothing left to align.

Q. Both a paramagnetic bar and an iron nail are attracted towards a magnet. What, physically, is the difference?

A. In a paramagnet, each atom has its own moment but the atoms act independently, so thermal motion keeps the alignment feeble — the attraction is tiny. In iron (a ferromagnet, next subsection), the atomic moments cooperate and lock together in large groups, producing an enormously stronger response. The difference in χ is a factor of many thousands.

Three samples have magnetic susceptibilities \(\chi_1 = -0.8 \times 10^{-5}\), \(\chi_2 = +2.2 \times 10^{-5}\) and \(\chi_3 = +2400\) at room temperature. (a) Classify each sample as diamagnetic, paramagnetic or ferromagnetic. (b) Calculate the relative permeability \(\mu_r\) of each sample. (c) Which sample would be weakly repelled by a strong magnet?

5.5.3 Ferromagnetism

Ferromagnetic substances are those which get strongly magnetised when placed in an external magnetic field. They have a strong tendency to move from a region of weak magnetic field to a region of strong magnetic field — i.e., they get strongly attracted to a magnet. This is the familiar, dramatic magnetism of everyday experience: iron filings leaping onto a magnet.

The individual atoms (or ions or molecules) in a ferromagnetic material possess a dipole moment, just as in a paramagnetic material. However — and this is the crucial new feature — they interact with one another in such a way that they spontaneously align themselves in a common direction over a macroscopic volume called a domain. The explanation of this cooperative effect requires quantum mechanics and is beyond the scope of this textbook.

NoteDefinition

A domain is a macroscopic volume inside a ferromagnetic material within which the atomic magnetic moments are spontaneously aligned in a common direction, giving the domain a net magnetisation.

Each domain has a net magnetisation. A typical domain size is 1 mm, and a domain contains about \(10^{11}\) atoms — an enormous team of atoms all pointing the same way. In the first instant, however, the magnetisation varies randomly from domain to domain, so their contributions cancel and there is no bulk magnetisation. This is shown in Fig. 5.9(a): the material as a whole is unmagnetised even though each domain individually is fully magnetised.

Fig. 5.9

Fig. 5.9 – Ferromagnetic domains (a) randomly oriented and (b) aligned by an external field.

When we apply an external magnetic field \(\vec{B}_0\), two things happen: the domains orient themselves in the direction of \(\vec{B}_0\), and simultaneously the domains already oriented in the direction of \(\vec{B}_0\) grow in size at the expense of their neighbours. This existence of domains and their motion in \(\vec{B}_0\) are not speculations. One may observe them under a microscope after sprinkling a liquid suspension of powdered ferromagnetic substance on the sample; the motion of the suspension can be observed directly. Figure 5.9(b) shows the situation when the domains have aligned and amalgamated to form a single ‘giant’ domain.

Thus, in a ferromagnetic material the field lines are highly concentrated — compare the modest crowding of Fig. 5.8(b) with what iron does, where \(\mu_r\) can exceed 1000. In a non-uniform magnetic field, the sample tends to move towards the region of high field, and does so strongly.

We may wonder what happens when the external field is removed. Here ferromagnets split into two useful classes.

In some ferromagnetic materials, the magnetisation persists even after the field is removed. Such materials are called hard magnetic materials or hard ferromagnets. Alnico — an alloy of iron, aluminium, nickel, cobalt and copper — is one such material. The naturally occurring lodestone, the very stone from our chapter-opening story, is another. Such materials form permanent magnets, to be used among other things as compass needles.

On the other hand, there is a class of ferromagnetic materials in which the magnetisation disappears on removal of the external field. Soft iron is one such material. Appropriately enough, such materials are called soft ferromagnetic materials. They are ideal wherever we want magnetism on demand — magnetised while the field is on, neutral the moment it is off.

There are a number of elements which are ferromagnetic: iron, cobalt, nickel, gadolinium, etc. The relative magnetic permeability of ferromagnets is greater than 1000!

The ferromagnetic property depends on temperature. At a high enough temperature, a ferromagnet becomes a paramagnet: the thermal agitation grows strong enough to break up the cooperative order, and the domain structure disintegrates. (This transition temperature is called the Curie temperature of the material.) This disappearance of magnetisation with temperature is gradual, not sudden.

This completes the answer to the last of our opening questions. Iron is special because its atoms not only carry permanent magnetic moments but also cooperate, locking together into domains that can be aligned into one giant magnet. Heating destroys a magnet because thermal agitation dismantles this delicate domain order — beyond a certain temperature, proud ferromagnetic iron behaves like just another weak paramagnet.

Q5. What is special inside iron that lets it become a strong permanent magnet, and why does heating a magnet destroy its magnetism?

A. Iron is special because its atoms carry permanent magnetic moments that also cooperate, locking together over small regions called domains; these domains can be aligned so the whole piece acts as one large magnet. Heating destroys the magnetism because thermal agitation dismantles this domain order — above a certain temperature (the Curie temperature) the ordered arrangement breaks down, and the once-ferromagnetic iron behaves like an ordinary weak paramagnet.

Q. A permanent magnet is dropped repeatedly on a hard floor and is found to become weaker. Why?

A. Mechanical shocks jolt the domains, allowing some of them to rotate back towards random orientations. The partial loss of domain alignment means partial loss of net magnetisation — the same reason heating (a kind of internal agitation) weakens a magnet.

In examinations, this section is a favourite for conceptual and assertion–reason questions: distinguishing dia-, para- and ferromagnetic behaviour from the sign and size of \(\chi\), explaining domain behaviour, contrasting hard and soft ferromagnets, and describing the effect of temperature. Table 5.2, together with the microscopic pictures above, covers nearly all of them.

5.6 Summary

  1. The science of magnetism is old. It has been known since ancient times that magnetic materials tend to point in the north–south direction; that like magnetic poles repel and unlike ones attract; and that cutting a bar magnet in two leads to two smaller magnets, each complete with both poles. Magnetic poles cannot be isolated.

  2. When a bar magnet of dipole moment \(\vec{m}\) is placed in a uniform magnetic field \(\vec{B}\):

    1. the net force on it is zero,
    2. the torque on it is \(\vec{\tau} = \vec{m} \times \vec{B}\),
    3. its potential energy is \(U_m = -\vec{m}\cdot\vec{B}\), where we choose the zero of energy at the orientation when \(\vec{m}\) is perpendicular to \(\vec{B}\).
  3. Consider a bar magnet of size \(l\) and magnetic moment \(\vec{m}\), at a distance \(r\) from its mid-point, where \(r \gg l\). The magnetic field \(\vec{B}\) due to this bar is:

\[\vec{B} = \frac{\mu_0\vec{m}}{2\pi r^3} \quad \text{(along axis)}\]

\[= -\frac{\mu_0\vec{m}}{4\pi r^3} \quad \text{(along equator)}\]

The axial field is parallel to \(\vec{m}\) and twice as strong as the equatorial field at the same distance, which points opposite to \(\vec{m}\).

  1. Gauss’s law for magnetism states that the net magnetic flux through any closed surface is zero:

\[\phi_B = \sum_{\substack{\text{all area} \\ \text{elements } \Delta\vec{S}}} \vec{B}\cdot\Delta\vec{S} = 0\]

This expresses the fact that there are no sources or sinks of \(\vec{B}\) — magnetic monopoles do not exist.

  1. Consider a material placed in an external magnetic field \(\vec{B}_0\). The magnetic intensity is defined as

\[\vec{H} = \frac{\vec{B}_0}{\mu_0}\]

The magnetisation \(\vec{M}\) of the material is its net dipole moment per unit volume. The total magnetic field \(\vec{B}\) inside the material is

\[\vec{B} = \mu_0(\vec{H} + \vec{M})\]

  1. For a linear material, \(\vec{M} = \chi\vec{H}\), so that \(\vec{B} = \mu\vec{H}\), where \(\chi\) is called the magnetic susceptibility of the material. The three quantities — \(\chi\), the relative magnetic permeability \(\mu_r\), and the magnetic permeability \(\mu\) — are related as follows:

\[\mu = \mu_0\mu_r\] \[\mu_r = 1 + \chi\]

Only one of the three is independent; given any one, the other two follow.

  1. Magnetic materials are broadly classified as diamagnetic, paramagnetic and ferromagnetic. For diamagnetic materials, \(\chi\) is negative and small; for paramagnetic materials, it is positive and small. Ferromagnetic materials have large \(\chi\).

  2. Substances which, at room temperature, retain their ferromagnetic property for a long period of time are called permanent magnets.

Physical Quantities at a Glance
Physical quantity Symbol Nature Dimensions Units Remarks
Permeability of free space \(\mu_0\) Scalar [MLT\(^{-2}\)A\(^{-2}\)] T m A\(^{-1}\) \(\mu_0/4\pi = 10^{-7}\)
Magnetic field, magnetic induction, magnetic flux density \(\vec{B}\) Vector [MT\(^{-2}\)A\(^{-1}\)] T (tesla) \(10^4\) G (gauss) = 1 T
Magnetic moment \(\vec{m}\) Vector [L\(^{-2}\)A] A m\(^2\)
Magnetic flux \(\phi_B\) Scalar [ML\(^2\)T\(^{-2}\)A\(^{-1}\)] W (weber) W = T m\(^2\)
Magnetisation \(\vec{M}\) Vector [L\(^{-1}\)A] A m\(^{-1}\) Magnetic moment / Volume
Magnetic intensity, magnetic field strength \(\vec{H}\) Vector [L\(^{-1}\)A] A m\(^{-1}\) \(\vec{B} = \mu_0(\vec{H} + \vec{M})\)
Magnetic susceptibility \(\chi\) Scalar – – \(\vec{M} = \chi\vec{H}\)
Relative magnetic permeability \(\mu_r\) Scalar – – \(\vec{B} = \mu_0\mu_r\vec{H}\)
Magnetic permeability \(\mu\) Scalar [MLT\(^{-2}\)A\(^{-2}\)] T m A\(^{-1}\), N A\(^{-2}\) \(\mu = \mu_0\mu_r\); \(\vec{B} = \mu\vec{H}\)

5.7 Points to Ponder

  1. A satisfactory understanding of magnetic phenomena in terms of moving charges and currents was arrived at only after 1800 AD. But the technological exploitation of the directional properties of magnets — the compass — predates this scientific understanding by two thousand years. Thus, scientific understanding is not a necessary condition for engineering applications. Ideally, science and engineering go hand-in-hand, one leading and assisting the other in tandem.

  2. Magnetic monopoles do not exist. If you slice a magnet in half, you get two smaller magnets, never a lone pole. On the other hand, isolated positive and negative electric charges do exist. There exists a smallest unit of charge — the electronic charge, with value \(|e| = 1.6 \times 10^{-19}\) C — and all other charges are integral multiples of this smallest unit. In other words, charge is quantised. Curiously, we do not know why magnetic monopoles do not exist, or why electric charge is quantised. Both remain open questions at the foundations of physics.

  3. A direct consequence of the fact that magnetic monopoles do not exist is that magnetic field lines are continuous and form closed loops. In contrast, the electrostatic lines of force begin on a positive charge and terminate on the negative charge (or fade out at infinity). One picture has no ends; the other always does.

  4. A minuscule difference in the value of the magnetic susceptibility \(\chi\) yields radically different behaviour: diamagnetic versus paramagnetic. For diamagnetic materials \(\chi = -10^{-5}\), whereas \(\chi = +10^{-5}\) for paramagnetic materials. The magnitudes are the same tiny number — only the sign differs, yet one substance creeps away from a magnet while the other creeps towards it.

  5. There exists a perfect diamagnet — namely, a superconductor. This is a metal at very low temperatures. In this case \(\chi = -1\), \(\mu_r = 0\), \(\mu = 0\): the external magnetic field is totally expelled. Interestingly, this material is also a perfect conductor. However, there exists no classical theory which ties these two properties together. A quantum-mechanical theory by Bardeen, Cooper and Schrieffer (the BCS theory) explains these effects. The BCS theory was proposed in 1957 and was eventually recognised by a Nobel Prize in Physics in 1970.

  6. Diamagnetism is universal — it is present in all materials, since every atom has orbiting electrons. But it is weak and hard to detect if the substance is para- or ferromagnetic, because those stronger effects mask it completely.

  7. We have classified materials as diamagnetic, paramagnetic and ferromagnetic. However, there exist additional types of magnetic material — such as ferrimagnetic, anti-ferromagnetic, spin glass, etc. — with properties which are exotic and mysterious. The three-way classification of this chapter is the beginning of the subject, not the end.

5.8 NCERT Questions

  1. A short bar magnet placed with its axis at \(30°\) with a uniform external magnetic field of \(0.25\) T experiences a torque of magnitude equal to \(4.5 \times 10^{-2}\) J. What is the magnitude of the magnetic moment of the magnet?

  2. A short bar magnet of magnetic moment \(m = 0.32\) J T\(^{-1}\) is placed in a uniform magnetic field of \(0.15\) T. If the bar is free to rotate in the plane of the field, which orientation would correspond to its (a) stable, and (b) unstable equilibrium? What is the potential energy of the magnet in each case?

  3. A closely wound solenoid of 800 turns and area of cross section \(2.5 \times 10^{-4}\) m\(^2\) carries a current of \(3.0\) A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?

  4. If the solenoid in Question 3 is free to turn about the vertical direction and a uniform horizontal magnetic field of \(0.25\) T is applied, what is the magnitude of the torque on the solenoid when its axis makes an angle of \(30°\) with the direction of the applied field?

  5. A bar magnet of magnetic moment \(1.5\) J T\(^{-1}\) lies aligned with the direction of a uniform magnetic field of \(0.22\) T.

    1. What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment: (i) normal to the field direction, (ii) opposite to the field direction?
    2. What is the torque on the magnet in cases (i) and (ii)?
  6. A closely wound solenoid of 2000 turns and area of cross-section \(1.6 \times 10^{-4}\) m\(^2\), carrying a current of \(4.0\) A, is suspended through its centre allowing it to turn in a horizontal plane.

    1. What is the magnetic moment associated with the solenoid?
    2. What is the force and torque on the solenoid if a uniform horizontal magnetic field of \(7.5 \times 10^{-2}\) T is set up at an angle of \(30°\) with the axis of the solenoid?
  7. A short bar magnet has a magnetic moment of \(0.48\) J T\(^{-1}\). Give the direction and magnitude of the magnetic field produced by the magnet at a distance of \(10\) cm from the centre of the magnet on (a) the axis, (b) the equatorial lines (normal bisector) of the magnet.

5.9 Check Your Concepts

  1. A bar magnet is cut into four equal pieces, first transverse to its length and then along its length. How many complete magnets are obtained? Will any piece have only a north pole? Justify your answer using the solenoid picture of a bar magnet.

  2. Magnetic field lines and electrostatic field lines both use the tangent to indicate field direction, and neither can intersect. State the one property in which the two kinds of field lines differ fundamentally, and name the physical fact about nature that this difference reflects.

  3. A magnetised needle placed in a uniform magnetic field experiences zero net force, yet it rotates when released from a non-aligned orientation. Explain how both statements can be true simultaneously.

  4. Two positions of a compass needle in a uniform magnetic field correspond to zero torque: \(\theta = 0°\) and \(\theta = 180°\). A student claims both are equilibrium positions and therefore both are equally stable. Point out the error in this claim using the expression for magnetic potential energy.

  5. A closed Gaussian surface is drawn so that it encloses only the north-pole end of a long bar magnet. A student argues that since “field lines come out of a north pole,” the net magnetic flux through this surface must be positive. Is the student correct? Explain.

  6. The magnetic intensity \(H\) inside a current-carrying solenoid remains unchanged when its air core is replaced by a soft iron core, but the magnetic field \(B\) increases enormously. Explain why one quantity changes and the other does not.

  7. A small bar of material X moves slowly towards the strong-field region of a non-uniform magnetic field, while an identical-looking bar of material Y moves slowly towards the weak-field region. Neither response is strong. Classify X and Y, and describe what happens to the magnetic field lines inside each bar.

    1. Why does a paramagnetic sample display greater magnetisation when cooled, whereas the diamagnetic response of a sample is nearly independent of temperature? (b) Why does a ferromagnet lose its ferromagnetism gradually, rather than abruptly, as it is heated?
  8. An electromagnet used in an electric bell must lose its magnetism the instant the current stops, while a magnet used in a magnetic compass must retain its magnetism for years. Which class of ferromagnetic material is suitable for each purpose? Give one example of each.

5.10 Practice with Numericals

  1. A short bar magnet experiences a torque of \(6.0 \times 10^{-2}\) N m when its axis makes an angle of \(60°\) with a uniform magnetic field of \(0.40\) T. Calculate (a) the magnetic moment of the magnet, and (b) the work done in rotating it from this orientation to the orientation of stable equilibrium.

  2. A closely wound solenoid has 500 turns, each of area \(4.0 \times 10^{-4}\) m\(^2\), and carries a current of \(2.5\) A. It is placed with its axis at \(45°\) to a uniform magnetic field of \(0.30\) T. Calculate (a) the magnetic moment of the solenoid, (b) the magnitude of the torque acting on it, and (c) its potential energy in this orientation.

  3. A short bar magnet has a magnetic moment of \(1.2\) J T\(^{-1}\). At what distance from its centre, on the axis, is the magnitude of the magnetic field equal to \(3.0 \times 10^{-5}\) T? What is the magnitude of the field at the same distance on the equatorial line?

  4. A magnetic field of magnitude \(2.0 \times 10^{-3}\) T passes through a circular loop of radius \(7.0\) cm, making an angle of \(30°\) with the plane of the loop. Calculate the magnetic flux through the loop. If this loop is one face of a closed surface, what is the net magnetic flux through the entire closed surface?

  5. A solenoid with 600 turns per metre carries a current of \(1.5\) A. Its core is a material of magnetic susceptibility \(\chi = 599\). Calculate (a) the magnetic intensity \(H\), (b) the magnetisation \(M\), (c) the magnetic field \(B\) inside the core, and (d) the relative permeability of the core material.

  6. The magnetic susceptibility of a superconductor is \(\chi = -1\). A sample of a superconducting material is placed in an external magnetic intensity \(H = 5.0 \times 10^{3}\) A m\(^{-1}\). Calculate (a) the magnetisation \(M\) of the sample, and (b) the magnetic field \(B\) inside it, and state what your answer to (b) implies physically.